Java loops | HackerRank Problem Solution :




Problem :

Given an integer, , print its first  multiples. Each multiple  (where ) should be printed on a new line in the form: N x i = result.

Input Format

A single integer, .

Constraints

Output Format

Print  lines of output; each line  (where ) contains the  of  in the form:
N x i = result.

Sample Input

2

Sample Output

2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
2 x 10 = 20

Solution 1:

	import java.util.*; import java.io.*;
	import java.text.*;
	import java.math.*;
	import java.util.regex.*;
	public class Solution {
	public static void main(String[] args) {
	Scanner scanner = new Scanner(System.in);
	int N = scanner.nextInt();
	for(int i = 1; i <=10; i++)
	{
	System.out.println(N + " x "+i+" = "+N*i);
	}
	}
	}

Solution 2:
import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;


public class Solution {
    public static void main(String[] args) throws IOException {
        Scanner scanner = new Scanner(System.in);
        int N = scanner.nextInt();
        
        if(N>=2||N<=20){
            
            for(int i =1;i<=10;i++){
                System.out.println(N+" x "+i+" = "+N*i);
            }
        }
       
    }
}